A thermodynamic system goes from states (i) P₁, V to 2P₁, V (ii) P, V₁ to P, 2V₁. Then work done in the two cases is(a) zero, zero(b) zero, PV₁(c) PV₁, zero(d) PV₁, P₁V₁
Answers
Answered by
5
Answer:
B) zero, PV₁
Explanation:
According to the concept of thermodynamic system -
Work done = area under curve = P ∙ ΔV
Case 1 where, (P, V) to (2P, V) where volume is constant -
Therefore W = P ∙ ΔV = P × 0
= 0
Case 2 where, (P, V) to (P, 2V) where volume is constant -
Therefore, W = P 2V ∫V dv
= P (2V – V)
= PV
Thus the work done in the two cases is zero, PV₁
Similar questions