Question

A thermodynamic system is taken from an original state to an intermediate state by the linear process shown in Fig. (12.13)



Its volume is then reduced to the original value from E to F by an isobaric process. Calculate the total work done by the gas from D to E to F

Answer 1

Concept :- workdone by a thermodynamics system = area under P-V curve and V - axis.
Work done is positive , if volume increases and negative , if volume decreases .

Solution :- work done in the process of DE = area inclosed by DEHGD
= area of ∆DEF + area of FRHG
= 1/2 × DF × EF + EF × FG
= 1/2 × ( 600-300)× (5 - 2) + 300 × (5 -2)
=( 450 + 900 ) Joule
= 1350 J

Workdone in process EF = - [ area inclosed by EFGH ]
= - 300 × ( 5 - 2)
= -900 J

Total workdone = workdone in process DE + workdone in process EF
= 1350 - 900
= 450 J

Answer 2

Answer:

450J

Explanation:

remember that for a cyclic process change in internal energy is 0.

that means the heat supplied is entirely used to do work.

W=P(change in volume)

=> W=area under the graph.

refer attachment for complete answer.

hope this helps.

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