A thermodynamic system undergoes cyclic process ABCDA
as shown in fig. The work done by the system in the cycle
is : [2014]
(a) P₀V₀
(b) 2P₀V₀
(c) P₀ V₀/2
(d) Zero
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Answer:
Work done in process ODA=1/2×P
o
×V
o
While work done in the process OBC=
2
−1
P
o
V
o
∴net W=0
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