Question

A thick wire of resistance 5 ohm is drawn into a thinner wire of 3 times the length of the thick wire find its new resistance ​

Answer 1

Thus the combined effect of stretching the wire to 3x its original length, while simultaneously decreasing its cross-sectional area by 3x, increases the resistance by a factor of 3 • 3 = 9, resulting in a final stretched resistance of 5Ω • 9 = 45Ω (ohms).

Answer 2

Answer:

45 Ohm

Explanation:

Whenever a wire having R resistance is stretched ( length increased and area decreased by same factor ) 'n' times. Then the resistance of the wire formed or new wire is (n)²•R.

Implying it we get new resistance = (3)²•5 = 45 Ohms.