Question

a thief is running with acceleration 1m/s^2 and a police is chasing the thief with velocity 20m/s.After what time police will catch the thief​

Answer 1

Just suppose both Policeman and thief are running in the same direction.

Given :-

Acceleration of Thief = 1 m/s²

Velocity of Police = 20 m/s

Using the first equation of motion :-

v = u + at

20 = 1 × t

t = 20 s

Note :-

1. The velocity of Policeman must be more than that of thief otherwise the thief will never be caught.

2. When both will have equal velocity then also thief can never be caught.

3. Relative Velocity of theif w.r.t police will be lesser than that of relative velocity of police w.r.t thief.