Question

A thief is stopped by a policeman from a distance of 400 metres. when the policeman starts the chase, the thief also starts running. assuming the speed of the thief as 5 km/h and that of policeman as 9 km/h, how far the thief would have run, before he i s over - taken by the policeman?

Answer 1

here is ur answer..........

Answer 2

Given:

Distance between the police and the thief = 400 m

Speed of the thief = 5 km/h

Speed of the police = 9 km/h

To FInd:

The distance that the thief would have ran before he was caught by the police.

Solution:

Define x:

Let the distance that the thief have ran be x

Distance that the thief ran = x km

Distance that the police ran = (0.4 + x) km

Find the time that the thief ran:

$\text{Time } = \dfrac{Distance }{Speed}$

$\text{Time } = \dfrac{x }{5}$

Find the time that the police ran:

$\text{Time } = \dfrac{Distance }{Speed}$

$\text{Time } = \dfrac{x + 0.4 }{9}$

Solve x:

$\dfrac{x }{5} = \dfrac{x + 0.4}{9}$

$5x + 2 = 9x$

$9x - 5x = 2$

$4x = 2$

$x = \dfrac{1}{2} \text{ km}$

Answer: The thief would have ran for another 0.5 km before the police catch up with him.