A thin copper wire of length L increases in length by 2% when heated from T1 to T2. If a copper cube having side 10L is heated from T1 to T2, What will be the percentage change in area of one face of the cube and volume of the cube.
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Increase in the size of the side=2% of 10l +10l
New length=1/5l+10l
New length=10.2l
area of one face=104.04l^2
Volume=1061.208l^3
Percentage change of area of one face=4.04/100×100=4.04%
Percentage change in volume=61.208/1000×100=6.1%
Hope this helps.
New length=1/5l+10l
New length=10.2l
area of one face=104.04l^2
Volume=1061.208l^3
Percentage change of area of one face=4.04/100×100=4.04%
Percentage change in volume=61.208/1000×100=6.1%
Hope this helps.
lzed:
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