Physics, asked by aabhamisra, 1 year ago

A thin disc of radius R and mass M has charge q uniformly distributed on it. It rotates with angular velocity w. The ratio of magnetic moment and angular momentum for the disc is
(1) q/2M (2) R/2M (3) q^2/2M (4) 2M/q

Answers

Answered by xerilee89
43

The formula to get  angular momentum (L) is

 L=Iw or L= \frac{mR^{2}w}{2}

where

I= moment inertia for a disk which is \frac{mR^{2}}{2}

The formula for magnetic moment (M) is

M=\frac{qR^{2}w}{4}

Therefore the ratio of magnetic moment to angular moment is

M/L.

\frac{\frac{qR^{2}w}{4}}{\frac{mR^{2}w}{2}}

(\frac{qR^{2}w }{2} )(\frac{2}{mR^{2} }w)

\frac{q}{2m}

Therefore, the ratio is q/2m.

Similar questions