Question

A thin rectangular magnet suspended freely has a period of oscillation equal to T . now , it is broken into two equal halves ( each having half of the original length ) and one piece is made to oscillate freely in the same field . if its period of oscillation is T' , the ratio T'/T is . [AIEEE 2003] ​

Answer 1

Answer:

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Explanation:

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Answer 2

Answer:

The ratio of T' /T = 1/2

Explanation:

When magnet is divided into two equal parts , the magnetic dipole moment

M' =pole strength × L/2 = M/2

[∵ pole strength remains same ]

Also , the mass of magnet become half i.e ...

m' = m/2

Moment of inertia of magnet ,I = ml²/12

New moment of inertia of magnet ,

• I' = 1/12(m/2)(l/2)² = ml²/12×8

• I'= I/8

• Now , T = 2π√(I/MB)

• T' = 2π(√I' /M'B) = 2 π √I /8/MB/2)

• = ∴ T' = T /2

• => T'/T = 1/2 Answer

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