Question

Find the general equation of the straight line passing through the points (-1, 1) and (2, -4).

Answer 1

Answer:

5x+3y+2=0

Step-by-step explanation:

the formula for the general equation of a straight line is

y-y₁=m(x-x₁)

where,

(x₁,y₁) are coordinates of one of the point.

m is the slope of the line.

slope of the line (m) = (y₁-y₂)/(x₁-x₂)

                                 = 1+4/-1-2

                                 = -5/3

so, now according to the slope point form,

y-1 = -5/3 (x+1)

=> 3y-3 = -5x-5

=> 5x+3y-3+5=0

=> 5x+3y+2=0