The distance between two stations is 340 km. Two trains start simultaneously from these stations on parallel tracks to cross each other. The speed of one of them is greater than that of the other by 5 km/hr. If the distance between the two trains after 2 hours of their start is 30 km, find the speed of each train.
Answers
Let the speed of the first train be x km/hr.
“The speed of one of them is greater than that of the other by 5 km/hr.”
Therefore, speed of second train is (x + 5) km/hr.
“The distance between the two trains after 2 hours of their start is 30 km.”
Time = 2 hrs and distance = 30 km
The distance that first train travel in 2 hours = 2x
And for second train, distance = 2(x + 5) = (2x + 10)
“The distance between two stations is 340 km.”
⇒ (340 - 30)km = 310 km
According to question,
⇒ 2x + 2x + 10 = 310
⇒ 4x = 310 - 10
⇒ 4x = 300
⇒ x = 75
Therefore,
Speed of first train = 75 km/hr
Speed of second train = 75 + 5 = 80 km/hr
Given :-
- Distance b/w two stations is = 340km.
- Speed of Faster train is 5km/h more Than slower Train.
- After 2 hours Distance b/w them is 30km.
Solution :-
Let us assume That, Speed of Slower Train is x km/h.
So, Speed of Faster Train will be (x + 5)km/h.
Now, we have Given That, Total Distance b/w them was 340 km and after 2 hours distance b/w them is 30km.
So, we can say That, Both Train covers Rest (340-30) = 310 km in 2 hours.
So,
→ Distance cover in 2 hours = 310km.
→ Distance cover by both in 1 hours = (310/2) = 155km. ----- Equation (1).
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Now, we know That, in Opposite Direction Speed is Sum of Both Train Speed .
So,
→ Distance covered by both train in 1 hour = (x) + (x + 5) = (2x + 5) km. -------- Equation (2).
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From (1) & (2) ,
→ 2x + 5 = 155
→ 2x = 155 - 5
→ 2x = 150
→ x = 75km.
Hence,