Question

A thin ring as a mass 0.25kg and radius 0.5m.calculate mi. 1) axis passing through center and perpendicular to length. 2) about a dimeter. 3) tangent perpendicular to plane.​

Answer 1

Answer:

(1)MOI about an axis passing through its center and perpendicular to its plane=MR

2

=0.5×0.25×0.25=31.25×10

−3

kg/m

2

(2)MOI about an an axis passing through a point on its circumference and perpendicular to its plane=MR

2

+md

2

=2MR

2

since,(d=R)

=0.0625kg/m

2

(3)MOI about diameter as the axis=

2

MR

2

=0.015625kg/m

2

Explanation:

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Answer 2

Answer:

0.01562kg/m

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