A thin ring has mass 0.25 kg and radius 0.5 m . Its moment of inertia about an axis passing through its centre and perpendicular to its plane is _____ .
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radius is 0.5m hence diameter =1.0m.
weight =0.25 kg.
inertia =mass*diameter
=0.25*1
=0.25
weight =0.25 kg.
inertia =mass*diameter
=0.25*1
=0.25
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