Question

A thin sheet of positive charge attracts a light charged sphere having a chařge
-5x100c with a force of 1.695 N . If €° 8.85x°10–12 C?/Nm2.
Calculate the surface density of the charge.​

Answer 1

Explanation:

please check your data.if data is correct then solve accordingly

Answer 2

Correct Question:

A thin sheet of positive charge attracts a light charged sphere having a charge -5×10^(-8) C with a force of 1.695 N. If €° 8.85x°10–12 C?/Nm2.

Calculate the surface density of the charge.

Calculation:

Let force experienced by sphere be F :

$\sf \therefore \: F = q \times E$

$\sf \implies \: F = q \times \bigg( \dfrac{ \sigma}{2 \epsilon_{0} } \bigg)$

$\sf \implies \: 1.695 = 5 \times {10}^{ - 8} \times \bigg( \dfrac{ \sigma}{2 \times 8.85 \times {10}^{ - 12} } \bigg)$

$\sf \implies \: 1.695 = 5 \times {10}^{ - 8} \times \bigg( \dfrac{ \sigma}{17.7 \times {10}^{ - 12} } \bigg)$

$\sf \implies \: 1.695 = {10}^{ - 8} \times \bigg( \dfrac{ \sigma}{3.54 \times {10}^{ - 12} } \bigg)$

$\sf \implies \: 1.695 = \dfrac{ \sigma}{3.54 \times {10}^{ - 4} }$

$\sf \implies \: \sigma = 1.695 \times (3.54 \times {10}^{ - 4} )$

$\sf \implies \: \sigma = 6.003\times {10}^{ - 4} \: C/ {m}^{2}$

So, the surface charge density is 6.003 × 10^(-4) C/m².