Question

A thin wire 40 cm long is formed into a rectangle. If the width of this rectangle is 8 cm,
what is its length?

Answer 1

Answer:

5cm

Step-by-step explanation:

perimeter of rectangle=length of wire=40cm

width=8cm

so, length of rectangle=40÷8=

5cm

Answer 2

Answer:

Question-

A thin wire 40 cm long is formed into a rectangle. If the width of this rectangle is 8 cm,

what is its length?

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Given -

↬Total length of wire(Perimeter) = 40cm

↬Breadth = 8 cm

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To find -

Length of the rectangle.

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Solution -

The length of the wire used to cover the box is the Perimeter of the rectangular box.

➼‎ ‎So, now we will find the length from the given perinter that is 40 cm and breadth that is 8 cm.

Let's take the length as =x cm

$\color{black}\boxed{\colorbox{saffron}{Perimeter-2(length+breadth) }}$

40= 2(8+x)

40= 16+2x

40-16= 2x

24=2x

$\frac{24}{2}$=x

12=x

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Required Answer -

$\rightarrow$Length of the given rectangular box = x = 12cm