Question

A thin wire is bent in the form of an equilateral triangle of side 11 cm. If the same wire is bent in the form of circle, find its area.
With the best explanation.

Answer 1

Answer:

86.625 cm²

Step-by-step explanation:

Find the length of the wire:

Length = 11 + 11 + 11 = 33 cm

Find the radius:

Circumference = 2πr

33 = 2πr

r = 33/2π

r = 5.25 cm

Find the area:

Area = πr²

Area = π(5.25)² = 86.625 cm²

Answer: The area is 86.625 cm²

Answer 2

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$\bold{\underline{Question-}}$ A thin wire is bent in the form of an equilateral triangle of side 11 cm.If the same wire is bent in the form of circle, find its area.
With the best explanation.

$\bold{\underline{Answer-}}$ According to the question we know that side of triangle is 11 cm .and triangle is a equilateral triangle so, the length is 11*3 = 33 we, need to find area or radius

Now,

Radius of circumference is 2πr

$= > \: \: \: \: \: \: 33 = 2\pi \: r$

$= > r = \frac{33}{2\pi \: }$

$= > r \: = 5.25$

Then, area of circumference is πr²

$= > \pi \: ( 5.25 ){}^{2}$

$= > \: \: 86.625 \: cm {}^{2}$