A THING FOR U....
que no 11
plz help...
no sparm....
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hey
the answer is below
let us assume that √7 is rational and hence is in the form of p/q where pa and q are co primes
so, √7=p/q
√7q=p
squaring the both sides
7q^2=p^2
this means seven divides p^2 so 7 also divides p
let p = 7c
7q^2 =49c^2
q^2= 7c^2
this means 7 divides q^2 so 7 also divides q
thus q and p have 7 as their common factor and this contradicts our statement that p and q are co primes because our assumption that √7 is rational was wrong, thus √7 is irrational
the answer is below
let us assume that √7 is rational and hence is in the form of p/q where pa and q are co primes
so, √7=p/q
√7q=p
squaring the both sides
7q^2=p^2
this means seven divides p^2 so 7 also divides p
let p = 7c
7q^2 =49c^2
q^2= 7c^2
this means 7 divides q^2 so 7 also divides q
thus q and p have 7 as their common factor and this contradicts our statement that p and q are co primes because our assumption that √7 is rational was wrong, thus √7 is irrational
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