A three digit number 4a3 is added to another three digit number 984 to give a four digit number 13b7,which is divisible by 11,find the value of 2a+b
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4a3+984=13(8+a)7 from here a can be 0 and 1 only. so 8+a=b .
form divisbilty rule of 11
7+3-(b+1)=9-b must be divisible by 11 .
so b=9 satisfy and a=1
2a+b= 11
form divisbilty rule of 11
7+3-(b+1)=9-b must be divisible by 11 .
so b=9 satisfy and a=1
2a+b= 11
nkhelwar:
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