a three digit number 4bc is divisible by 15. what are the values of band c for the smallest such number.
Answers
Answered by
5
Answer:
b=0 and c=5
Step-by-step explanation:
4bc is divisible by 15
15=3*5.thus it is divisible by 3 and 5 both
i) divisibility by 3
sum of digits of 4bc
=4+b+c is divisible by 3
ii) Divisibility by 5
unit digit c =0 or 5
If c=0
then 4+b+c=4+b disivisible by 3
for smallest number b=5
So No=450
If c=5
then 4+b+c=4+b+5=9+b
b can be zero,Then No =405
So possible number are 450 or 405
The smallest No=405
so b=0 and c=5
Answered by
5
Answer:
b = 0 , c = 5
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