A three digit number is such that its digit at ten’s place is 1 more than the digit at hundred’s place. The sum of the digits is 13. The number obtained by reversing the digits can be obtained by multiplying the original number with 2 and subtracting 49 from this product. Find the original number
Answers
Answered by
0
HY FRIEND ,
let,
hundred place digit be x
tens place digit be 13-10x+1
before reversing,
100x+13-10x+1
90x+14
after reversing,
(90x+14)2
180x+28-49
180x-21
90x+14=180x-21
90x=35
x=35/90
Hope it help
let,
hundred place digit be x
tens place digit be 13-10x+1
before reversing,
100x+13-10x+1
90x+14
after reversing,
(90x+14)2
180x+28-49
180x-21
90x+14=180x-21
90x=35
x=35/90
Hope it help
fcbraihanpe0ash:
wrong
Similar questions