If f(x) = log x^3 then d/dx f(x) =3/x^n then the value of n is
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(1/x^3)*3*x^2= 3/x so value of n is 1
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d/dx f(X)=1/x^3×3x^2
3/X=3/x^n
then
n=1
I hope help for you
3/X=3/x^n
then
n=1
I hope help for you
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