A three phase induction motor is driving full-load torque which is independent of
speed. If the line voltage drops to 90% of the rated value, % increase in motor copper
losses
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If the line voltage drops to 90% of the rated value, % increase in motor copper losses will be 23 %
Explanation :
For an induction motor, when the torque is constant then,
sV² = constant
=> s₁V₁² = s₂V₂²
=> s₂V₂/s₁V₁ = V₁/V₂ = 1/0.9 = 1.11
we know that current is proportional to product of slip and voltage
=> I ∝ sV
=> I₂/I₁ = s₂V₂/s₁V₁ = 1.11
We know that the copper loss of an induction motor is directly proportional to square of the current
=> C₂/C₁ = (I₂/I₁)² = 1.11² = 1.23
Hence increase in copper loss = 0.23 = 23 %
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