find b^2x^2 + a^2y^2 -- a^2b^2 if x=acos* and y=bsin*
Answers
Answered by
1
Answer:-
b^2x^2 + a2y 2 - a^2b^2
= b^2(acos?)^2 + a^2(bsin?)^2 - 262
- b 2 a 2 cos 2?+ a*2b 2sin 22 -a 2b 2
= a^2b 2 (cos^2? + sin^2?) - a^2b^2
Since, cos 2? + sin 2? 1
a2b 2 (1)-a 2b 2
=0
b^2x^2 + a2y 2 - a^2b^2
= b^2(acos?)^2 + a^2(bsin?)^2 - 262
- b 2 a 2 cos 2?+ a*2b 2sin 22 -a 2b 2
= a^2b 2 (cos^2? + sin^2?) - a^2b^2
Since, cos 2? + sin 2? 1
a2b 2 (1)-a 2b 2
=0
Similar questions