Question

a)Three resistor 2Ω,4Ω and 5Ω are combined in parallel. What is the total resistance of the combination ? b) If the combination is connected to a battery emf 20V and negligible internal resistance determine the current through each resistor, and the total current drawn from the battery

Answer 1

1/Rp=1/2+1/4+1/5

=0.5+0.25+0.2

=0.95 ohm

Answer 2

Answer:

Step-by-step explanation:

Let three resistance be R1,R2 and R3

When connected in parallel:

1/Rp=1/R1+ 1/R2 + 1/R3

=1/2 +1/4+1/5

=10/20+5/20+4/20

=19/20

Rp =20/19

Rp =1.05Ω

V=20V

For R1

I=V/R1

=10amp

For R2

I=V/R2

=5amp

For R3

I=V/R3

=4amp

I=V/Req

=19.04amp

Hope it helps!!!