Question

A tiger chases a dear 30 m ahead of it and gains 3 m in
5 s after the chase started. After 10 s, the distance
between them is
(1) 6m
(2) 14 m (3) 18 m (4) 24 m​

Answer 1

Answer:

Answer:the distance is 24m

According to me

Answer 2

help. Add your answer and earn points.

Brainly User

hii mate!!

=> relative initial velocity(assuming both start from rest for a neutral ground observer) = vₐ - vᵦ = 0 

relative acceleration = aₐ - aᵦ 

relative distance covered in 5 s (deer at relative rest) = 3 m 

=> s = ut + ½at² 

=> 3 = 0t + ½[aₐ - aᵦ](5)² 

=> aₐ - aᵦ = relative acceleration = 3/12.5 = 0.24 m/s² 

=> the distance gained by the tiger in 10sec(neutral observer) = 0t + ½[aₐ - aᵦ](10)² = .24 x 50 = 12 m 

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