Question

A tiger chases a deer 30m ahead of it and gains 3m in 5s. After the chase starts. After 10s the distance between them is

Answer 1

Distance between they is 30m

speed of tiger is 3 m in five seconds = v

now two case are possible

1.)
now if we suppose that deer is standing there only and not moving than after 10 seconds distance between them will be 24 m

2.)
if deer is not standing but moving let say with velocity of y than
here we have to find distance between them by relative velocity formula,

v-y = x / 10
x = (v-y)10 meter
x = ((3/5)-y)10 meter.............. answer


note
here v = speed of tiger
y = speed of deer
x = distance between them after 10 seconds

Answer 2

Answer:

Explanation:

Here it is the implementation of relative velocity.