Question

A tile has the shape of a parallelogram whose base is 35 cm and the corresponding height is 10 cm.How many tiles are required to cover a floor of area 84000 cm².​

Answer 1

Explanation:

Base of the tile = 35cm

Corresponding height = 10cm

Area of the tile (parallelogram) = b*h

= 35 (10) = 350 sq cm

Area of the floor = 84000 sq cm

No of tiles required = 84000/350

= 8400/35

= 240

No of tiles required to cover a floor = 240

Answer 2

${ \huge{ \underline{ \underline{ \sf{ \green{GivEn : }}}}}}$

• Base of Tile = 35cm

• Shape of Tile = parallelogram

• Area of floor = 84000cm²

• Height of tile = 10cm

${ \huge{ \underline{ \underline{ \sf{ \green{To \: find :}}}}}}$

• Number of tiles required to cover a floor of area 84000cm².

Formula to be used :-

• Area of parallelogram = Base × Height

${ \huge{ \underline{ \underline{ \sf{ \green{SoluTion : }}}}}}$

At first, we need to find the area of 1 tile

Area of 1 tile

= Base × Height

= 35 × 10

= 350 cm²

Given that,

Area of floor is = 84000cm²

_________________________________________________

Hence,

Number of tiles required to cover floor

= Area of floor/Area of 1 tile

= 84000/350

= 240

Therefore ,number of tiles required to cover a floor of area 84000cm² is = 240