Question

A tin can has dimentions 2m x1.5 x 1m. Howmany litres of kerosene oil can it hold

Answer 1

The cuboid will hold $3\ L$ of the kerosene oil.

Step-by-step explanation:

Given the dimension of the tin is $2\ m\times 1.5\ m\times 1\ m$.

We need to find how much oil in liters would this cuboid holds?

As we know that $1\ m^3=1\ L$

We will find the volume of this cuboid. That will be  

$l\times b\times h$

$2\ m\times 1.5\ m\times 1\ m=3\ m^3$

Since $1\ m^3=1\ L$

The cuboid will hold $3\ L$ of the kerosene oil.

Answer 2

Answer:

The can holds 3000 liters of kerosene oil

Solution:

Given that,

Tin can has dimensions 2 m x 1.5 m x 1 m

We have to find the liters of kerosene oil can it hold

Find the volume of can

Volume\ of\ tin\ can = length \times width \times heightVolume of tin can=length×width×height

Therefore,

\begin{gathered}Volume = 2 \times 1.5 \times 1\\\\Volume = 3\ m^3\end{gathered}

Volume=2×1.5×1

Volume=3 m

3

Convert to liters

1\ m^3 = 1000\ liter1 m

3

=1000 liter

Therefore,

3\ m^3 = 3000\ liters3 m

3

=3000 liters

Thus the can holds 3000 liters of kerosene oil