Question

A tin maker bought a sheet of tin of length 4.40 cm and width 1.16 m. He
made cylindical tins closed on both the sides of height 20 cm and radius 7 cm
while making each tin 88 cm2. Sheet is wasted then how many tins can be
made from that sheet?​

Answer 1

Given =

length of sheet = 4.40m = 440 cm

width = 1.16m = 116cm

Radius = 7cm

Height = 20cm

so, the area of given size sheet will be = length * width

= 440 * 116

= 51040 square cm

Now the area of sheet required for making one tin =

$2\pi \: rh \: + \: 2\pi \: r {?}^{2}$

= 2*22/7 * 7*20 + 2 * 22/7 * 7sq

= 880 + 308

according to the question 88cm sq sheet is wasted in making one tin

so the total area of sheet required to make one tin =

= 1188/88

= 51040/1276

= 40

Answer 2

Step-by-step explanation:

Given =

length of sheet = 4.40m = 440 cm

width = 1.16m = 116cm

Radius = 7cm

Height = 20cm

so, the area of given size sheet will be = length * width

= 440 * 116

= 51040 square cm

Now the area of sheet required for making one tin =

2\pi \: rh \: + \: 2\pi \: r {?}^{2}2πrh+2πr?

2

= 2*22/7 * 7*20 + 2 * 22/7 * 7sq

= 880 + 308

according to the question 88cm sq sheet is wasted in making one tin

so the total area of sheet required to make one tin =

= 1188/88

= 51040/1276

= 40