A tire has a radius (outer radius) of 10 inches. A small mark is painted at the very top of the tire, and then the tire is rolled forward slightly so that the mark rotates through an angle of pi/4 radians. Identify how far above the ground is the mark at this point?
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Given A tire has a radius (outer radius) of 10 inches. A small mark is painted at the very top of the tire, and then the tire is rolled forward slightly so that the mark rotates through an angle of pi/4 radians. Identify how far above the ground is the mark at this point?
- Consider a tire which is in the form of a circle with radius 10 inches. Mark appoint at the top of the tire.
- Now roll the tire forward so that the mark rotates through making an angle π/4 radians or 45 degree.
- Now there are two positions like the original mark and the new mark.
- We need to find the distance or height of the mark above the ground.
- Therefore we have height = 10 + a
- So sin 45 = a / 10
- Or a = 10 x sin 45
- = 10 x 1/√2
- = 10 x 0.707
- = 7.07 inches.
- Now height = 10 + a
- = 10 + 7.07
- = 17.07 inches.
- Therefore the mark is 17.07 inches above the ground
Reference link will be
https://brainly.in/question/13241080
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