Physics, asked by tanmaytak5374, 1 year ago

A torch bulb is rated 2.5 v and 750ma calculate its power

Answers

Answered by anshikaroy3456
2

Answer:

Given :

V=2.5 V

I=750mA= 750x10⁻³A

power =p=?

Power =V*I            

 =2.5x750x10⁻³

=1.875W

Answered by omegads04
1

Given potential difference V = 2.5 V and

Current I = 750 mA = 0.750 A

We know power P = VI

P = 2.5 × 0.750 =  1.875 W

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