Physics, asked by Anonymous, 2 months ago

A torch bulb is rated 5v and 500mA. Calculate its
1.power
2. Resistance
3. Energy consumed when its highted for 5/2 hours.​

Answers

Answered by anshuverma6397
1

Answer:

change 500mA=0.5A.

now, power =VI

p=5×0.5=2.5W.

V=IR=R=V/I=5/0.5=10ohm.

w=pt=2.5*5/2=12.5/2=6.25WH.

Answered by rohithraju038
1

Explanation:

This means that the bulb works when a voltage of 5V is applied across it and 500mA of current flows through it. Hence, the power dissipated across the torch bulb is equal to 2.5W . Hence, the resistance of the bulb is equal to 10Ω . Hence, the energy consumed by the bulb is equal to 36kJ .

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