A torch bulb is rated 5V and 500mA. Calculate its (i) power, (ii) resistance, (iii) energy
consumed when it is lighted for 4 hours.
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Step-by-step explanation:
Given, i= 500mA
V= 5V
(i) power=VI
=5× 500 ×0.001
=2.5 watt
(ii) V=IR
R=5÷(500×0.001)
=10 ohm
(iii) Energy dissipated as heat will be
H=VIt
=5×500×0.001×4×60×60
=36000 joule.
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6
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