a torch bulb is rated 5volt and 500mA. calculate the 1.power 2.resistance 3.energy consumed when it is lighted for 4 hours??
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Answer:
This means that the bulb works when a voltage of 5V is applied across it and 500mA of current flows through it. Hence, the power dissipated across the torch bulb is equal to 2.5W . Hence, the resistance of the bulb is equal to 10Ω . Hence, the energy consumed by the bulb is equal to 36kJ .
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Given
Potential difference =V=5V
Current =I= 500mA=500x/1000 A=0.5 A
I) Power = V X I
= 5x0.5 =5x5/10=2.5 W
II)Reistance =R=?
By Ohm's law: V=IR
R=V/I
R=5/0.5
=50/5 =10 ohms
III)Energy consumed when it is lighted for 4 hours
Energy =Power x time
t=4hrs=4x60x60
=2.5x 4x60x60
=36000joules/sec
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