A torch bulb is rated at 3V and 600 mA calculate its (a) power (b) resistance (c) energy consumed if lighted for 4 hrs
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use the formula V=IR
V=3v
convert I what is 600 mA as 6A
the resistance is R=V/I
R=3V/6A=1.5 ohm
power is VI
3*6=18 W
if lighted for 4 hours energy consumed
18*4=72 Wh
V=3v
convert I what is 600 mA as 6A
the resistance is R=V/I
R=3V/6A=1.5 ohm
power is VI
3*6=18 W
if lighted for 4 hours energy consumed
18*4=72 Wh
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