Question

A torch bulb is rated at 3v and 600ma. calculate it's

a.power

b.resistance

c.energy consumed if it is lighted for 4 hrs.

Answer 1

Given value of V = 3V and I = 600mA = 0.6A
so Power(P) = VI = 3*0.6 = 1.8 watt
Resistance (R) = P/I^2 = 1.8/0.36 = 5ohm
Energy (E) = P*t = 1.8 * 4 * 3600 = 25920 Joule.

Answer 2

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