Find the tn11 term of 7 13 19 25
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The ratio of the sum of n terms of two A.P.s is (7n+1):(4n+27).
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Hii dear here is your answer.... ....
◆a=7
◆d=a2-a1
=13-7
=6
a11=a+(n-1)d
◆7+(11-1)6
◆7+60
67 is the tn11 of the A.P
◆a=7
◆d=a2-a1
=13-7
=6
a11=a+(n-1)d
◆7+(11-1)6
◆7+60
67 is the tn11 of the A.P
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