A torch bulb iscrated 5v and 500 ma calculate power of bulb and resistance of bulb
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Answered by
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Answer:
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Given :
Potential difference = 5V
Current = 500mA = 500x / 1000A = 0.5A
i) Power of bulb = V × I
= 5 × 0.5
= 5 x 5/10
= 2.5 W
ii) Resistance = R = ?
By Ohm's law: V = IR
R = V/I
R = 5/0.5
= 50/5
= 10 Ω
#Be Brainly❤️
=======
Answer:
=======
Given :
Potential difference = 5V
Current = 500mA = 500x / 1000A = 0.5A
i) Power of bulb = V × I
= 5 × 0.5
= 5 x 5/10
= 2.5 W
ii) Resistance = R = ?
By Ohm's law: V = IR
R = V/I
R = 5/0.5
= 50/5
= 10 Ω
#Be Brainly❤️
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Answered by
1
Here Potential difference, V= 5v Current, I=500mA=500/1000A =0.5A Now, a) Power = V.I =5*0.5 =2.5W b) From ohm's law, V=RI R=V/I =5/0.5 =10 ohm c) Time for which the bulb is lighted, t =4 h =4*3600s =14400s Energy consumed, H =VIt = 5*0.5*14400 =36000J
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