Physics, asked by AryanParadshinge, 7 months ago

A torch bulb of 4.5 V, draws a current of 0.3 A. If the bulb is switched on for

10 minutes, calculate the energy released by the bulb.​

Answers

Answered by 18020134
0

Answer:

The answer is 810 J

Explanation:

H= VIt

= 4.5 x 0.3 x 600 (10 X 60 = 600 S/c)

= 4.5 x 0.3 x 6 x 100

= 4.5 x 10 x 0.3 x 10 x 6 (10 x 10 =100)

= 45 x 3 x 6

= 45 x 18

= 810J

Answered by Anonymous
1

Given - Voltage, current and time

Find - Energy released

Solution - Energy released can be calculated as the product of voltage, current and time. Representing this in mathematical expression -

E = V*i*t

Converting time into seconds. As per the known fact, 1 minute = 60 seconds.

So, 10 minutes = 60*10

Performing multiplication

10 minutes = 600 seconds.

Keep the values in formula to find the heat.

E = 4.5*0.3*600

Performing multiplication

E = 810 Joules

Hence, the energy released by bulb is 810 Joules.

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