Question

A toroidal coil has a magnetic path length of 33 cm and a magnetic field strength of 650 AT/m. The coil current is 250 mA. Determine the number of coil turns.
A. 858 turns
B. 85 turns​

Answer 1

Answer:

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Answer 2

Answer:

The correct option is A) 858 turns

Explanation:

Given Data :

Length of the coil(l) = 33 cm = 0.33 m

Magnetic field Strength (h) = 650 A/m

Current = 250 mA = 0.25 A

Let n be the number of turns.

Formula to be Used =

$h \: = \frac{ni}{l}$

Calculations :

$n \: = \frac{hl}{i} = \frac{650 \times 0.33}{0.25} = 858$

Hence, The number of coil turns = 858.

Definition of Magnetic Field Strength :

• The portion of a material's magnetic field that results from an external current and is not intrinsic to the material itself is known as the magnetic field strength, also known as magnetic intensity or magnetic field intensity.
• It is measured in amperes per metre and represented as the vector H.

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