Question

A torque of 1500nm acting on a body produces an angular acceleration

Answer 1

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Answer 2

The moment of inertia of the body is $I=468.75\ kg-m^2$.

Explanation:

Given that,

Torque acting on a body, $\tau=1500\ N-m$

If the angular acceleration of the body, $\alpha =3.2\ rad/s^2$

We need to find the moment of inertia of the body. The relation between the angular acceleration, torque and moment of inertia is given by :

$\tau=I\alpha$

$I=\dfrac{\tau}{\alpha }$

$I=\dfrac{\1500\ N-m}{3.2\ rad/s^2}$

$I=468.75\ kg-m^2$

So, the moment of inertia of the body is $I=468.75\ kg-m^2$. Hence, this is the required solution.

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Moment of inertia

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