Question

A torque of 400 Nm acting on a body of mass 40 kg produces an angular acceleration of 20 rad/s². Calculate the moment of inertia and radius of gyration of the body.
(Ans.: 20 kgm², 0.707 m)

Answer 1

as we know

torque=I@

400=I*20

so,I=20kgm2

and for radius of gyration use

K=√I/m

where K=radius of gyration

and I=moment of inertia

Answer 2

Hey Trishala,

◆ Answer -

I = 20 kgm^2

R = 0.707 m

◆ Explanation -

# Given -

α = 20 rad/s^2

τ = 400 Nm

m = 40 kg

# Solution -

Moment of inertia is calculated as -

I = τ / α

I = 400 / 20

I = 20 kgm^2

Radius of gyration is calculated as -

R = √(I / m)

R = √(20 / 40)

R = √(1/2)

R = 0.707 m

Hope this helps you.