Math, asked by uttamds8980, 11 months ago

A total of 1400kg of potatoes were sold in three days on the first day 100 kg less potatoes were sold than on second day and on third day , 3/5th of amount sold on first day how many kg of potato were sold

Answers

Answered by shivanireddy42
8

Answer:

500

Step-by-step explanation:

let no of potatoes sold on 2nd day be B

no of potatoes sold on 1st day=(B-100)

no of potatoes sold on 3rd day=3*(B-100)/5

1st day +2nd day + 3rd day=1400

B-100 + B + 3*(B-100)/5=1400

B=600

no of potatoes sold on 2nd is 600

no of potatoes sold on 1st day is B-100= 600-100=500

Answered by sikarwarronak99
2

Answer:

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