Question

A total of x litres of pure acid were drawn from a tank containing 729 litres of pure acid and were replaced by water the result was thoroughly mixed to obtain a homogenous solution and then another x litres of solution were drawn off and again replaced by water, and thoroughly mixed. This procedure was repeated six times and the tank then contained 64 litres of pure acid. Determine x.

Answer 1

As acid was removed six times in the quantity of x , therefore a total of 6x litres of acid were removed.

So,
729 - 6x = 64
6x = 729 - 64
6x = 665
x = 665/6
= 110 5/6 litres or 110.83 litres (approximately).

Answer 2

Answer:

The value of 'x' is 110.83 litres.

Explanation:

We know that the 'x' amount of acid was removed at once.

This 'x' amount was removed six times.

Therefore, the total amount of acid removed = 6x

After removing 6x litres of acid from 729 litres, 64 litres of acid was left.

∴ $729-6x=64$

∴$6x=729=64$

∴$6x=665$

∴$x=665/6$

∴ x= 110.83

Thus, the value of 'x' is 110.83 litres.