Question

a tourist box with a mass of 120 kg is at rest. a balikbayan pushes the box with horizontal net force of 300N in 15 seconds what is the distance it will travel in this period​

Answer 1

Answer:

To get balance, the moment of lift has to equal the moment due to the weight. The weight needs to be converted to force (1kg = 9.81N at sea level).

So the equation is:

300 (N) * 2.4 (m) = 120 * 9.81 (N) * d

where d is the distance of the box from the fulcrum (in metres)

Solving for d gives

d = (300 * 2.4) / (120* 9.81) = 0.61m

d will need to be less than this to compensate for the weight of the lever and to actually get the box to lift.

Explanation:

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