A tower AB is 20 m high and BC , its shadow on ground , is 20√3 m long. Find the sun's altitude.
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Answered by
5
tan= 20/20√3
tan= 1/√3
30
tan= 1/√3
30
Answered by
11
tan@= Height of tower/shadow of tower
=20/20root3
=1/root3
@ = 30 degree
now
let distance between sun and earth is d
tan30=sun's altitude /distance between sun and earth
d/root3=sun's altitude
=20/20root3
=1/root3
@ = 30 degree
now
let distance between sun and earth is d
tan30=sun's altitude /distance between sun and earth
d/root3=sun's altitude
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