A tower ab is 20m high and bcits shadow on the ground is 20root3m long find the altitude
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bro u can solve it with the help of trigonometry ratio
thnkss
thnkss
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hey mate!!!
here is your answer...
From the figure,
AB=20m
BC=20√3 m
tan angle ACB = AB /BC
tan angle ACB =20/20√3
=1/√3
angle ACB = 30°
hope it helps you...
plz mark it as brainiest...
here is your answer...
From the figure,
AB=20m
BC=20√3 m
tan angle ACB = AB /BC
tan angle ACB =20/20√3
=1/√3
angle ACB = 30°
hope it helps you...
plz mark it as brainiest...
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