A tower is 20 m high and its shadow on the ground
is 20√3 m long. Find the angle of elevation of the sum
Answers
Answered by
0
Answer:
<ACB = 30°
Step-by-step explanation:
Height of the tower = AB = 20 m
Length of the shadow = BC = 20√3 m
the altitude of the Sun = <ACB
tan <ACB = AB/CB
= 20/20√3
= 1/√3
tan <ACB = tan 30°
<ACB = 30°
Answered by
4
Answer: the angle of elevation of sun is 30°
Step-by-step explanation: tanA =20/20√3
tanA =1/√3
tanA = tan 30°
A(angle of elevation) =30°
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