Question

A tower is 50√ 3 m high. The angle of elevation of its top from a point 50 m away from its foot has measure ......,select a proper option (a), (b), (c) or (d) from given options so that the statement becomes correct.
(a) 45
(b) 60
(C) 30
(d) 15

Answer 1

Dear Student,

Answer: Option b ( 60°) is correct

Solution:

As height of tower is 50√3 m

Distance of observer 50 m

In a right angle triangle perpendicular and base is given.

and we know that from trigonometric ratio

tan thetha = perpendicular/ base

tan thetha = 50√3/50
tan thetha = √3

angle of elevation = tan-1 (√3)
angle of elevation = 60°


Hope it helps you

Answer 2

Height of the tower ( OB ) = 50√3 m

OA = 50m

Angle elevation ( x° ) = <OAB

In ∆AOB , <AOB = 90°

tan x° = OB/AO

= 50√3/50

= √3

tan x° = tan 60°

Therefore ,

x° = 60°

Angle of elevation = x = 60°

Option ( b ) is correct.

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