A Tower is 50 metre high its shadow is shorter when the sun altitude is 45 degree than when it is 30 degree.
find the value of x
Answers
Answer:
Refer to the attachment for ur answer.....
Step-by-step explanation:
Given.,tower height = 50 m
Sun’s altitude is 45°when it is 30°.
To find:
Find the value of x which means the shadow shorter to the nearest cm = ?
Solution:
The height of the tower is 50 m high
The length of the shadow is X, when the shadow is being casted at an angle of 45 degrees
When the length of the shadow is being casted at 30 degrees the length of the shadow is X + 50
Therefore, the value of X is
tan45
∘
=
length of the shadow at 45
A
tan45
∘
=
50
A
A=50
The length of the shadow is X, when the shadow is being casted at an angle of 45 degrees is 50 m
Hence, the length of the tower to the length of the shadow falls at 30 degree is
tan30
∘
=
length of the shadow at 30
50
3
1
=
x+50
50
x=50(
3
−1)
Therefore, the value of the X is
50(
3
−1)
=50×0.732∣
=36.6m
=3660cm